Find the particular solution to dydx=4x3\frac{dy}{dx} = 4x^3dxdy=4x3 with y(1)=2y(1) = 2y(1)=2.
y=x4+1y = x^4 + 1y=x4+1
y=x4−2y = x^4 - 2y=x4−2
y=x4+2y = x^4 + 2y=x4+2
y=4x4+2y = 4x^4 + 2y=4x4+2