Find the radical axis of the circles x2+y2=4x^2+y^2=4x2+y2=4 and x2+y2−2x−4y+1=0x^2+y^2-2x-4y+1=0x2+y2−2x−4y+1=0.
x+2y−2.5=0x+2y-2.5=0x+2y−2.5=0
x+2y−5=0x+2y-5=0x+2y−5=0
2x+4y−5=02x+4y-5=02x+4y−5=0
2x+4y+3=02x+4y+3=02x+4y+3=0