Find the radius of convergence for f(x)=∑n=0∞n!xn2f(x) = \sum_{n=0}^{\infty} n! x^{n^2}f(x)=∑n=0∞n!xn2.
R=1R = 1R=1
R=0R = 0R=0
R=∞R = \inftyR=∞
R=eR = eR=e