Find the radius of convergence for the series ∑n=1∞n!(x−5)n3n\sum_{n=1}^{\infty} \frac{n! (x-5)^n}{3^n}∑n=1∞3nn!(x−5)n.
R=0R=0R=0
R=3R=3R=3
R=1/3R=1/3R=1/3
R=∞R=\inftyR=∞