Find the radius of convergence of ∑n=1∞(n!)2(2n)!(x+3)n\sum_{n=1}^{\infty} \frac{(n!)^2}{(2n)!} (x+3)^n∑n=1∞(2n)!(n!)2(x+3)n.
R=1R = 1R=1
R=2R = 2R=2
R=4R = 4R=4
R=8R = 8R=8