Find the radius of curvature ρ=1/κ\rho = 1/\kappaρ=1/κ of the curve y=ln(x)y = \ln(x)y=ln(x) at the point (1,0)(1, 0)(1,0). Use κ=∣y′′∣(1+(y′)2)3/2\kappa = \frac{|y''|}{(1 + (y')^2)^{3/2}}κ=(1+(y′)2)3/2∣y′′∣.
111
2\sqrt{2}2
12\frac{1}{2}21
222\sqrt{2}22