Find the range of xxx for which x2−3x+2x2+x−2≤0\frac{x^2 - 3x + 2}{x^2 + x - 2} \leq 0x2+x−2x2−3x+2≤0.
(−2,1)(-2, 1)(−2,1)
[1,2][1, 2][1,2]
(−2,2](-2, 2](−2,2]
(−2,−1)∪(1,2](-2, -1) \cup (1, 2](−2,−1)∪(1,2]