Find the range of xxx for which 4−x2≥0\sqrt{4 - x^2} \geq 04−x2≥0.
−2≤x≤2-2 \leq x \leq 2−2≤x≤2
x≤2x \leq 2x≤2
x≥−2x \geq -2x≥−2
x<2x < 2x<2