Find the range of xxx for which x2−16≥3\sqrt{x^2 - 16} \geq 3x2−16≥3.
x≥5x \geq 5x≥5 or x≤−5x \leq -5x≤−5
x≥4x \geq 4x≥4
4≤x≤54 \leq x \leq 54≤x≤5
x≤−5x \leq -5x≤−5