Find the range of xxx such that x+2>x\sqrt{x+2} > xx+2>x.
x∈(−2,2)x \in (-2, 2)x∈(−2,2)
x∈[−2,2)x \in [-2, 2)x∈[−2,2)
x∈[0,2)x \in [0, 2)x∈[0,2)
x∈(−2,0)x \in (-2, 0)x∈(−2,0)