Find the range of xxx that satisfies ∣x2−4x−5∣<7|x^2 - 4x - 5| < 7∣x2−4x−5∣<7.
(−2,1)∪(3,6)(-2, 1) \cup (3, 6)(−2,1)∪(3,6)
(−2,6)(-2, 6)(−2,6) excluding {0,4}\{0, 4\}{0,4}
(−2,0)∪(4,6)(-2, 0) \cup (4, 6)(−2,0)∪(4,6)
(−1,5)(-1, 5)(−1,5)