Find the second partial derivative fxyf_{xy}fxy for the function f(x,y)=exycos(x)f(x,y) = e^{xy} \cos(x)f(x,y)=exycos(x).
exy(ycosx−sinx)e^{xy}(y \cos x - \sin x)exy(ycosx−sinx)
exy(xcosx−sinx)e^{xy}(x \cos x - \sin x)exy(xcosx−sinx)
exy(ycosx−xsinx)e^{xy}(y \cos x - x \sin x)exy(ycosx−xsinx)
000