Find the set of all real xxx that satisfy the inequality ∣x2−1∣−3x2−4≤0\frac{|x^2 - 1| - 3}{x^2 - 4} \leq 0x2−4∣x2−1∣−3≤0.
x∈(−2,−2)∪(−2,2)∪(2,2)x \in (-2, -2) \cup (-2, 2) \cup (2, 2)x∈(−2,−2)∪(−2,2)∪(2,2)
x∈[−2,−2]∪[2,2]x \in [-2, -2] \cup [2, 2]x∈[−2,−2]∪[2,2]
x∈(−2,−2)∪(2,2)x \in (-2, -2) \cup (2, 2)x∈(−2,−2)∪(2,2)
x∈(−2,−2)∪[−2,2]∪(2,2)x \in (-2, -2) \cup [-2, 2] \cup (2, 2)x∈(−2,−2)∪[−2,2]∪(2,2)