Find the set of all xxx where x2−1x2−4≤0\frac{x^2-1}{x^2-4} \leq 0x2−4x2−1≤0.
(−2,−1]∪[1,2)(-2, -1] \cup [1, 2)(−2,−1]∪[1,2)
[−1,1][-1, 1][−1,1]
(−2,2)(-2, 2)(−2,2)
(−∞,−2)∪(2,∞)(-\infty, -2) \cup (2, \infty)(−∞,−2)∪(2,∞)