Find the solution to y′=1+y2y' = 1 + y^2y′=1+y2 with y(0)=0y(0) = 0y(0)=0.
y=tan(x)y = \tan(x)y=tan(x)
y=arctan(x)y = \arctan(x)y=arctan(x)
y=tanh(x)y = \tanh(x)y=tanh(x)
y=sec2(x)y = \sec^2(x)y=sec2(x)