Find the sum of ∑n=0∞(−1)nπ2n+142n+1(2n+1)!\sum_{n=0}^{\infty} \frac{(-1)^n \pi^{2n+1}}{4^{2n+1} (2n+1)!}∑n=0∞42n+1(2n+1)!(−1)nπ2n+1.
3/2\sqrt{3}/23/2
22\frac{\sqrt{2}}{2}22
1/21/21/2
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