Find the value of ∫01xex2dx\int_0^1 x e^{x^2} dx∫01xex2dx using the substitution u=x2u = x^2u=x2.
12(e−1)\frac{1}{2}(e - 1)21(e−1)
eee
e−1e - 1e−1
12e\frac{1}{2}e21e