Find the value of sin(θ)\sin(\theta)sin(θ) if cos(2θ)=0.6\cos(2\theta) = 0.6cos(2θ)=0.6 and θ\thetaθ is in the first quadrant.
sin(θ)=1+0.62≈0.894\sin(\theta) = \sqrt{\frac{1 + 0.6}{2}} \approx 0.894sin(θ)=21+0.6≈0.894
sin(θ)=0.6\sin(\theta) = 0.6sin(θ)=0.6
sin(θ)=0.6≈0.775\sin(\theta) = \sqrt{0.6} \approx 0.775sin(θ)=0.6≈0.775
sin(θ)=1−0.62≈0.447\sin(\theta) = \sqrt{\frac{1 - 0.6}{2}} \approx 0.447sin(θ)=21−0.6≈0.447