Find the vertical asymptotes of f(x)=x2−9x3−2x2−3xf(x) = \frac{x^2-9}{x^3-2x^2-3x}f(x)=x3−2x2−3xx2−9.
x=0,x=−1x=0, x=-1x=0,x=−1
x=3,x=0,x=−1x=3, x=0, x=-1x=3,x=0,x=−1
x=3x=3x=3 only
x=3,x=−1x=3, x=-1x=3,x=−1