Find the general solution to y′=x−1y' = x - 1y′=x−1.
y=x−1+Cy = x - 1 + Cy=x−1+C
y=Cexy = C e^xy=Cex
y=x2−x+Cy = x^2 - x + Cy=x2−x+C
y=x2/2−x+Cy = x^2/2 - x + Cy=x2/2−x+C