Find the particular solution to y′=1/xy' = 1/xy′=1/x with y(1)=0y(1) = 0y(1)=0.
y=ln∣x∣y = \ln|x|y=ln∣x∣
y=ln∣x∣+1y = \ln|x| + 1y=ln∣x∣+1
y=1/x−1y = 1/x - 1y=1/x−1
y=ex−ey = e^x - ey=ex−e