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Recursionhard
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For an=2an−1−an−2+2na_n = 2a_{n-1} - a_{n-2} + 2nan​=2an−1​−an−2​+2n with a0=1,a1=2a_0 = 1, a_1 = 2a0​=1,a1​=2, find a4a_4a4​.