Recurrence Relationshard
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For an=4an14an2a_n = 4a_{n-1} - 4a_{n-2} with a0=2a_0 = 2 and a1=8a_1 = 8, the characteristic equation (r2)2=0(r-2)^2 = 0 gives the general solution an=(c1+c2n)2na_n = (c_1 + c_2 n) \cdot 2^n. What are c1c_1 and c2c_2?