For f(x)=sinxf(x) = \sin xf(x)=sinx, find the Taylor polynomial of degree 5 centered at x=0x=0x=0.
x−x36+x5120x - \frac{x^3}{6} + \frac{x^5}{120}x−6x3+120x5
1−x22+x4241 - \frac{x^2}{2} + \frac{x^4}{24}1−2x2+24x4
x−x33+x55x - \frac{x^3}{3} + \frac{x^5}{5}x−3x3+5x5
x+x36+x5120x + \frac{x^3}{6} + \frac{x^5}{120}x+6x3+120x5