For the Bernoulli equation y′+y=y2exy' + y = y^2 e^xy′+y=y2ex, what is the substitution to linearize it?
v=y−1v = y^{-1}v=y−1
v=y2v = y^2v=y2
v=lnyv = \ln yv=lny
v=y−2v = y^{-2}v=y−2