For the function f(x)={x2x≤23x−2x>2f(x) = \begin{cases} x^2 & x \leq 2 \\ 3x - 2 & x > 2 \end{cases}f(x)={x23x−2x≤2x>2, is fff continuous at x=2x=2x=2?
Yes, because limx→2−f(x)=limx→2+f(x)=f(2)=4\lim_{x \to 2^-} f(x) = \lim_{x \to 2^+} f(x) = f(2) = 4limx→2−f(x)=limx→2+f(x)=f(2)=4
No, because the left and right limits differ
No, because f(2)f(2)f(2) is undefined
Yes, but only from the right