For the rational function f(x)=x+2(x−1)(x+3)f(x) = \frac{x + 2}{(x-1)(x+3)}f(x)=(x−1)(x+3)x+2, which values are vertical asymptotes?
x=1x = 1x=1 and x=−3x = -3x=−3
x=−1x = -1x=−1 only
x=0x = 0x=0 only
x=−2x = -2x=−2 only