For the series ∑n=1∞3n2n3+1\sum_{n=1}^{\infty} \frac{3n^2}{n^3 + 1}∑n=1∞n3+13n2, what can we conclude from the divergence test?
The series converges by the divergence test
The series diverges because limn→∞3n2n3+1=0\lim_{n \to \infty} \frac{3n^2}{n^3 + 1} = 0limn→∞n3+13n2=0
The series diverges because limn→∞3n2n3+1≠0\lim_{n \to \infty} \frac{3n^2}{n^3 + 1} \neq 0limn→∞n3+13n2=0
We cannot determine convergence from the divergence test alone