For the series ∑n=1∞(x−3)nn\sum_{n=1}^{\infty} \frac{(x-3)^n}{n}∑n=1∞n(x−3)n, what is the center of the interval of convergence?
x=3x = 3x=3
x=0x = 0x=0
x=1x = 1x=1
x=−3x = -3x=−3