For what value(s) of mmm does the system {y=x2−3x+2y=mx+1\begin{cases} y = x^2 - 3x + 2 \\ y = mx + 1 \end{cases}{y=x2−3x+2y=mx+1 have exactly one real solution?
m=1m = 1m=1
m=−1m = -1m=−1
m=−1m = -1m=−1 or m=−5m = -5m=−5
m=5m = 5m=5 or m=−5m = -5m=−5