Determinantsmedium
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Given A=(2132)A = \begin{pmatrix} 2 & 1 \\ 3 & 2 \end{pmatrix} with det(A)=1\det(A) = 1, use the formula A1=1det(A)adj(A)A^{-1} = \frac{1}{\det(A)}\text{adj}(A) to find the (1,2)(1,2) entry of A1A^{-1}.