Given f(x)={kxx<2x2−kx≥2f(x) = \begin{cases} kx & x < 2 \\ x^2 - k & x \ge 2 \end{cases}f(x)={kxx2−kx<2x≥2, find kkk for continuity at x=2x=2x=2.
k=2k = 2k=2
k=4k = 4k=4
k=43k = \frac{4}{3}k=34
k=1k = 1k=1