Given f(x)=1b−af(x) = \frac{1}{b-a}f(x)=b−a1 for a≤x≤ba \leq x \leq ba≤x≤b, what is the variance σ2\sigma^2σ2?
(b−a)212\frac{(b-a)^2}{12}12(b−a)2
(b−a)26\frac{(b-a)^2}{6}6(b−a)2
a+b2\frac{a+b}{2}2a+b
b−a12\frac{b-a}{\sqrt{12}}12b−a