Given f(x)=x2−3x+2x2−1f(x) = \frac{x^2 - 3x + 2}{x^2 - 1}f(x)=x2−1x2−3x+2, which of the following is true about the graph of f(x)f(x)f(x)?
It has a vertical asymptote at x=1x=1x=1 and a hole at x=−1x=-1x=−1
It has a vertical asymptote at x=−1x=-1x=−1 and a hole at x=1x=1x=1
It has vertical asymptotes at both x=1x=1x=1 and x=−1x=-1x=−1
It has holes at both x=1x=1x=1 and x=−1x=-1x=−1