Given f(x,y)=ln(x2+y2)f(x, y) = \ln(x^2 + y^2)f(x,y)=ln(x2+y2), find the value of the Laplacian ∇2f=fxx+fyy\nabla^2 f = f_{xx} + f_{yy}∇2f=fxx+fyy.
4(x2+y2)2\frac{4}{(x^2 + y^2)^2}(x2+y2)24
000
2x2+y2\frac{2}{x^2 + y^2}x2+y22
1x2+y2\frac{1}{x^2 + y^2}x2+y21