Given ∫01f(x)dx=5\int_0^1 f(x) dx = 5∫01f(x)dx=5 and ∫01g(x)dx=−2\int_0^1 g(x) dx = -2∫01g(x)dx=−2, what is ∫01(3f(x)−4g(x)+2)dx\int_0^1 (3f(x) - 4g(x) + 2) dx∫01(3f(x)−4g(x)+2)dx?
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