Given that ex=∑n=0∞xnn!e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!}ex=∑n=0∞n!xn converges for all real xxx, evaluate the series ∑n=0∞1n!\sum_{n=0}^{\infty} \frac{1}{n!}∑n=0∞n!1.
eee
111
e−1e^{-1}e−1
e2\frac{e}{2}2e