Given that x=1x = 1x=1 is a root of p(x)=x3−1x2+x−1p(x) = x^3 - 1x^2 + x - 1p(x)=x3−1x2+x−1, factor p(x)p(x)p(x) completely.
(x−1)(x+1)(x - 1)(x + 1)(x−1)(x+1)
(x−1)(x2−1)(x - 1)(x^2 - 1)(x−1)(x2−1)
(x+1)(x2+1)(x + 1)(x^2 + 1)(x+1)(x2+1)
(x−1)(x2+1)(x - 1)(x^2 + 1)(x−1)(x2+1)