Given the differential equation dydx=x2y(1+x3)\frac{dy}{dx} = \frac{x^2}{y(1+x^3)}dxdy=y(1+x3)x2, determine the general solution.
y2=23ln∣1+x3∣+Cy^2 = \frac{2}{3} \ln |1+x^3| + Cy2=32ln∣1+x3∣+C
y2=13ln∣1+x3∣+Cy^2 = \frac{1}{3} \ln |1+x^3| + Cy2=31ln∣1+x3∣+C
y=23ln∣1+x3∣+Cy = \frac{2}{3} \ln |1+x^3| + Cy=32ln∣1+x3∣+C
y2=ln∣1+x3∣+Cy^2 = \ln |1+x^3| + Cy2=ln∣1+x3∣+C