Given the implicit relation exy=x+ye^{xy} = x + yexy=x+y, find the slope dydx\frac{dy}{dx}dxdy at the point (0,1)(0, 1)(0,1).
dydx=0\frac{dy}{dx} = 0dxdy=0
dydx=1\frac{dy}{dx} = 1dxdy=1
dydx=−1\frac{dy}{dx} = -1dxdy=−1
dydx=0.5\frac{dy}{dx} = 0.5dxdy=0.5