How is the intercept β0\beta_0β0 calculated if the slope β1\beta_1β1, xˉ\bar{x}xˉ, and yˉ\bar{y}yˉ are known?
β0=yˉ+β1xˉ\beta_0 = \bar{y} + \beta_1 \bar{x}β0=yˉ+β1xˉ
β0=xˉ−β1yˉ\beta_0 = \bar{x} - \beta_1 \bar{y}β0=xˉ−β1yˉ
β0=yˉ−β1xˉ\beta_0 = \bar{y} - \beta_1 \bar{x}β0=yˉ−β1xˉ
β0=β1xˉ−yˉ\beta_0 = \beta_1 \bar{x} - \bar{y}β0=β1xˉ−yˉ