Identify which point (x,y)(x, y)(x,y) lies on the curve x2−2y2=1x^2 - 2y^2 = 1x2−2y2=1.
(2,1)(2, 1)(2,1)
(3,2)(3, 2)(3,2)
(4,2)(4, 2)(4,2)
(5,3)(5, 3)(5,3)