If 0≤an≤bn0 \le a_n \le b_n0≤an≤bn for all nnn and ∑n=1∞bn\sum_{n=1}^{\infty} b_n∑n=1∞bn converges, what can we conclude about ∑n=1∞an\sum_{n=1}^{\infty} a_n∑n=1∞an?
∑n=1∞an\sum_{n=1}^{\infty} a_n∑n=1∞an diverges.
∑n=1∞an\sum_{n=1}^{\infty} a_n∑n=1∞an converges.
∑n=1∞an\sum_{n=1}^{\infty} a_n∑n=1∞an may converge or diverge.
∑n=1∞an\sum_{n=1}^{\infty} a_n∑n=1∞an has sum equal to ∑n=1∞bn\sum_{n=1}^{\infty} b_n∑n=1∞bn.