If 3x=73^x = 73x=7, solve for xxx in terms of natural logarithms.
x=7ln(3)x = 7 \ln(3)x=7ln(3)
x=ln(7)−ln(3)x = \ln(7) - \ln(3)x=ln(7)−ln(3)
x=ln(7)ln(3)x = \frac{\ln(7)}{\ln(3)}x=ln(3)ln(7)
x=ln(3)ln(7)x = \frac{\ln(3)}{\ln(7)}x=ln(7)ln(3)