If AAA and BBB are independent, what is P(Ac∣Bc)P(A^c | B^c)P(Ac∣Bc)?
P(Ac)P(A^c)P(Ac)
P(A)P(A)P(A)
1−P(B)1 - P(B)1−P(B)
P(A∣B)P(A|B)P(A∣B)