If AAA is a square matrix, which is always true?
AAA is diagonalizable
det(A)=det(AT)\det(A) = \det(A^T)det(A)=det(AT)
det(A)=tr(A)\det(A) = \text{tr}(A)det(A)=tr(A)
det(A)=det(A−1)\det(A) = \det(A^{-1})det(A)=det(A−1)