If a power series f(x)=∑n=0∞an(x−2)nf(x) = \sum_{n=0}^{\infty} a_n (x-2)^nf(x)=∑n=0∞an(x−2)n satisfies f(x)(1−x)=1f(x)(1 - x) = 1f(x)(1−x)=1, what is a0a_0a0?
a0=−1a_0 = -1a0=−1
a0=1a_0 = 1a0=1
a0=2a_0 = 2a0=2
a0=0a_0 = 0a0=0