If A⊂BA \subset BA⊂B, then P(A∣B)P(A|B)P(A∣B) is equal to:
P(A)/P(B)P(A) / P(B)P(A)/P(B)
P(B)/P(A)P(B) / P(A)P(B)/P(A)
P(A)P(A)P(A)
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