If A={x∈R:x2−5x+6≤0}A = \{x \in \mathbb{R} : x^2 - 5x + 6 \le 0\}A={x∈R:x2−5x+6≤0} and B={x∈R:x2−4x+3≥0}B = \{x \in \mathbb{R} : x^2 - 4x + 3 \ge 0\}B={x∈R:x2−4x+3≥0}, find A∩BA \cap BA∩B.
[1,2]∪{3}[1, 2] \cup \{3\}[1,2]∪{3}
[2,3]∪{1}[2, 3] \cup \{1\}[2,3]∪{1}
[1,2][1, 2][1,2]
[2,3][2, 3][2,3]