If an=c14n+c24nna_n = c_1 4^n + c_2 4^n nan=c14n+c24nn, find the recurrence.
an=8an−1−16an−2a_n = 8a_{n-1} - 16a_{n-2}an=8an−1−16an−2
an=4an−1−4an−2a_n = 4a_{n-1} - 4a_{n-2}an=4an−1−4an−2
an=16an−1−8an−2a_n = 16a_{n-1} - 8a_{n-2}an=16an−1−8an−2
an=2an−1−4an−2a_n = 2a_{n-1} - 4a_{n-2}an=2an−1−4an−2